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The probability that two cards drawn from a deck of cards are both aces?
Wiki User
∙ 13y ago
The probability of drawing two Aces from a standard deck of 52 cards is 4 in 52 times 3 in 51, or 12 in 2652, or 1 in 221, or about 0.00452.
Wiki User
∙ 13y ago
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Two cards are drawn from a standard deck of 52 cards without replacement Find the probability that both cards are aces?
There are 4 aces in the deck the odds that the first card is an ace is 4/52 or 1/13. The odds the second card is an ace is 3/51 or 1/17 because there are only 3 aces and 51 cards left. The odds that both are aces are 1/13 times 1/17 which is 1/221.
What is the probability of drawing two consecutive aces from a deck of fifty two cards?
If you are drawing only two cards, the probability that they will both be aces is one in 221. ( (52 / 4) * (51 / 3) ) If you are drawing all the cards in the deck, one at a time, the probability that you will draw at least two aces in a row is much better than that, but how much better I leave for someone else to answer.
What is the probability of pulling two red cards without replacement from a deck of cards?
Assuming a pack consists of 52 cards as per normal. Initially half the cards are red. Probability that the first card drawn is red = 1/2. Now there are 25 red cards left out of 51 remaining cards. Probability that the second card drawn is red = 25/51. Probability that both cards drawn are red therfore = 1/2 * 25/51 = 25/102
What suit of aces and eights did wild bill have?
Both pair of cards were clubs and spades.
A card is drawn from a standard deck of 52 playing cards Find the probability that the card is an ace or a black card?
This is a probability case of statistics using the addition rule P(A or B) = P(A) + P(B) - P(A and B). The output can happen at the same time, for that reason it is not mutually exclusive. The output can be an ace and a black card. first case: how many ace's we got=4 over the number of total cards=52 second case: how many black cards=26 over the total number of cards=52 BOTH cases: they can be just 2 cards that can be aces AND black. (4/52)+(26/52)-(2/52)= 7/13=.538461538462= .5385
Two cards are drawn from a standard deck of 52 cards without replacement Find the probability that both cards are aces?
There are 4 aces in the deck the odds that the first card is an ace is 4/52 or 1/13. The odds the second card is an ace is 3/51 or 1/17 because there are only 3 aces and 51 cards left. The odds that both are aces are 1/13 times 1/17 which is 1/221.
What is The probability that the first and second card drawn from a deck of 52 cards are both kings?
Two cards are drawn from a pack of 52 cards second card is drawn after replacing the first card. What is the probability that the second card is a king?
What is the probability of drawing two consecutive aces from a deck of fifty two cards?
If you are drawing only two cards, the probability that they will both be aces is one in 221. ( (52 / 4) * (51 / 3) ) If you are drawing all the cards in the deck, one at a time, the probability that you will draw at least two aces in a row is much better than that, but how much better I leave for someone else to answer.
Don randomly draws two cards from a standard deck of 52 cards. He does not replace the first card. What is the probability that both cards are aces?
1-221
What is the probability of pulling two red cards without replacement from a deck of cards?
Assuming a pack consists of 52 cards as per normal. Initially half the cards are red. Probability that the first card drawn is red = 1/2. Now there are 25 red cards left out of 51 remaining cards. Probability that the second card drawn is red = 25/51. Probability that both cards drawn are red therfore = 1/2 * 25/51 = 25/102
2 cards are drawn at random from a pack of 52 cards. find the probability that both the cards are spades?
well theprobability would be 2x52/4 which is about 26%
What is the probability that a random selected poker hand contains exactly 3 aces given that it contains at least 2 aces?
I will assume that you mean a five card poker hand. We can label the cards C1, C2, C3, C4, and C5. We are basically told already that C1 and C2 are both aces. So we have to find the probability that exactly one of C3, C4, and C5 is an ace. Knowing that the first two cards in our hand are both aces means that there are only 50 cards left in the deck. The probability that C3 is an ace and that C4 and C5 are both not aces is (2/50)(48/49)(47/48)=0.03836734694. The same probability also applies to each of C4 and C5, considered independently of each other. Therefore, our final probability is 3* 0.03836734694=0.1151020408
If a box contains three blue cards and three white cards If two cards are drawn one at a time find the probability that both cards are blue if the draws are made with replacement?
The probability of drawing two blue cards froma box with 3 blue cards and 3 white cards, with replacement, is 1 in 4, or 0.25.The probability of drawing one blue card is 0.5, so the probability of drawing two is 0.5 squared, or 0.25.
What is the probability of drawing two hearts from a standard pack of cards is 3 divided 51 what is the probability that the two cards drawn are not both hearts?
The probability of drawing a heart from a fair deck is 1 in 4. If the card is replaced then the probability is again 1 in 4. The probability of drawing a card other than a heart is 3 in 4. Once again if the card is replaced then the probability remains 3 in 4
What is the probability that both cards are spades?
The answer will depend on:whether the cards are drawn at random andwhether or not the first card is replaced before drawing the second.It also depends on how many times the experiment - of drawing two cards - is repeated. If repeated a sufficient number of times the probability will be so close to 1 as to make no difference from a certainty.
What suit of aces and eights did wild bill have?
Both pair of cards were clubs and spades.
If two cards are simultaneously drawn from a standard deck of cards what is the probability that they are not both the same suit?
The first card can be anything. That means that there are 51 cards left and 39 of them are not the same suit as the first one, therefore P(not same suit) = 39/51 = 13/17.
