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Q: The product of 2 consecutive odd numbers is 63 what is the larger number?

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9

7

6 times 7 = 42 and so 7 is the larger number

No two consecutive numbers have a product that is an even number. Any two consecutive numbers include one odd number and one even number. The product of one odd number and one even number is always an odd number.

The consecutive odd number with a product of 12099 are 109 and 111.

1332

The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).

There is no such number.

Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

The product of 2 consecutive positive number is 48. Find the 2 numbers

0,6,18,36,60,90,126,168, etc

the answer is 6

The largest number is 9.

1 and 2, whose product is 2.

Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.

There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)

9

-7

Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.

let n = {...-2,-1,0,1,2,3,4,...} then n+1 is the consecutive number. Their product is n(n+1) = n2 + n

No whole number would fit (their product would be even for starters).

The two numbers are 3 and 5 and so 5 is the larger number

Yes because at least one of the consecutive numbers will be even, and if you times anything by an even number, the answer will always be even

5,6,7

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