Not whole numbers, no.
Not possible in whole numbers
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
There are no such whole numbers. The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.
They are 12 and 15
The sum or product of three odd numbers will always be odd.
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
The sum of two numbers is a whole number if both of the numbers are whole numbers, or if the sum of two fractions can be simplified to a whole number.
No - the product of numbers is the answer to a multiplication sum, while the sum of numbers is the answer to an addition sum.
The three consecutive whole numbers you are looking for are 1, 2, and 3. The sum of the first two numbers, 1 + 2 = 3.
They are 9 and 5
12 and 3.
6 and 4
7 and 8
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
The numbers are 13 and 8 The product is 104
For this to be possible with whole numbers, 175 has to be a multiple of three. It's not, it isn't.
272 is the maximum possible.
34 and 36
The numbers are 15, 9, and 3.
The numbers are 9, 11 and 13.