12 and 3.
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∙ 12y ago141
7 and 8
six and nine
Zero and 15.
7*8 = 56. The further you move from the midpoint the smaller the multiple. So if you are not restricted to whole numbers, 7.5*7.5 = 56.25 is the largest possible product.
They are 12 and 15
141
7 and 8
There are none but: (15+square root of 129)/2 and (15-square root of 129)/2 will give a sum of 15 and a product of 24
six and nine
6+9=15 6*9=54
The sum of the first five whole numbers is 10.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
15 and 3
The numbers are: 3 and 12
Zero and 15.
The numbers are 15 and 3. 15 * 3 = 45 15 + 3 = 18