For the product to be zero, one of the numbers must be 0.
So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
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Not possible in consecutive integers, nearest is consecutive even integers: 148 & 152
Add the two greatest possible four digit numbers. 9999 + 9999
8
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).