1+100=101
The sum of the integers from 1 to 100 inclusive is 5,050.
101
n*(n+1)=sum 100*(100+1)=10100
The sum of the numbers from 1 through 100 is 5,050.
The sum of the integers from 1 to 100 can be calculated using the formula for the sum of an arithmetic series: ( S_n = \frac{n(n + 1)}{2} ), where ( n ) is the last integer in the series. Here, ( n = 100 ), so the sum is ( S_{100} = \frac{100(100 + 1)}{2} = \frac{100 \times 101}{2} = 5050 ). Therefore, the sum of the integers from 1 to 100 is 5050.
The sum of the whole numbers from 1 to 100 inclusive is 5,050.
Without just going and doing the addition, you can use this formula:Sum of 1 to N is: (N+1)*N/2. So take sum of [1 to 100], then subtract off the sum of [1 to 20], and you'll have left the sum [21 to 100].Sum [1-100] = (100+1)*100/2 = 5050. Sum[1-20] = (20+1)*20/2 = 210.So 5050 - 210 = 4840
You add the numbers in a loop. Here is an example in Java:int sum = 0;for (int i = 1; i
The following will sum all integers from 1-100. Adjust according to your needs.int sum = 0;for (int i = 1; i
int i, sum; /* example using while */ sum = 0; i = 1; while (i <= 100) { sum += i; ++i; } /* example using for */ sum = 0; for (i = 1; i <= 100; ++i) sum += i;
The sum of the first 100 counting numbers (1-100) is 5,001.
The sum of the all prime numbers from 1 to 100 is 1,161