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Q: The sum of 3 consecutive integers is 72 find the 3 integers?

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The sum of three consecutive integers is -72

The even integers are 22, 24 and 26.

Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37

Presumably the sum is -222, as defined by the question!

72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.

The numbers are -21, -19, -17 and -15.

There are none. However, the two odd numbers are 35 and 37.

The numbers are 8 and 9.

There are no two consecutive integers that add up to 72. You can prove it this way: Let our numbers be represented by the variables "a" and "b". We are told: a = b + 1 a + b = 72 So we can use substitution to solve for either variable: (b + 1) + b = 72 2b + 1 = 72 2b = 71 b = 35.5 But 35.5 is not an integer, so this condition can not be met.

35 and 37.

Since the three integers are consecutive, let them be: m, m+1, and m+2.Then:m + (m+1) + (m+2) = 72m + m + 1 + m + 2 = 3m + 3 = 723(m+1) = 72m+1 = 24m = 23So the three integers are: {23, 24, 25}. Check and they do in fact sum to 72.

The numbers are -26, -24, and -22. (all negative numbers can be considered odd or even).

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