72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
Let x, x+2 and x+4 be the three consecutive odd integers. x+2(x+2)+3(x+4)=70 x+2x+4+3x+12=70 6x+16=70 6x=54 x=9 The numbers are 9, 11, and 13 Check: 9+2(11)+3(13)= 9+22+39=70
Assuming the equation is 3x=15, you just need to divide each side of the equation by three. On the left, x times three divided by three is one times x, or just x. On the right side, fifteen divided by three is five. So you are left with x=5.
b = 3a ?
3000
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
The sum of three consecutive integers is -72
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
You've come to the right place. The integers are: 2, 4, and 6
The 3 consecutive odd positive integers are 7, 9 and 11.
12 and 13.
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
x+(n+1)+3(n+2)= something then solve,
18, 20 and 22
5872345098234783904672083946728390752430689723409687298290843 theres your answer
The integers are 5 and 7.
5, 7 and 9
-1, 1 and 3