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Q: The sum of its digits is 11?

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1 + 1 = 2 The sum of the digits is therefore 2.

The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.

The difference betweenthe sum of the digits in odd positions andthe sum of the digits in even positionsis divisible by 11.

65

22

By the sum of its digits: 10. By each of its individual digits: 11.

65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11

How about 65 because 6+5 = 11

65

The number 1111115

11 squared is 121

11

Sum the digits in the odd positions in the integer. Sum = XSum the digits in the even positions in the integer. Sum = YIf X - Y is a multiple (including negative or 0), then the given integer is divisible by 11.

83

12

65

65

what number is prime to 40 29 - it's a prime number (divisible only by 1 and itself) and if you sum the two digits 2 + 9 = 11

int Sum( int digits ) { if(digits < 10) return digits; return digits%10 + Sum(digits/10); }

the sum of my digits is 6? answer=60

11

11+1+1+1 =14

11

That would be 29.

Add the digits together. The sum of the digits of 23 is 5.