65
11
No integer fits those conditions.
Add together all the digits in the odd positions in the number. Sum = A Add together all the digits in the even positions in the number. Sum = B If A-B is 0 or if it divisible by 11 (positive or negative), then the original number is divisible by 11.
56
It you add up all the digit in the number they will total 11. For example the number 425 has digits that sum to 11. (4 + 2 + 5 = 11)
65
65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11
65
what number is prime to 40 29 - it's a prime number (divisible only by 1 and itself) and if you sum the two digits 2 + 9 = 11
83
12
How about 65 because 6+5 = 11
11
The number 1111115
By the sum of its digits: 10. By each of its individual digits: 11.
11