The difference betweenthe sum of the digits in odd positions andthe sum of the digits in even positionsis divisible by 11.
22
How about 65 because 6+5 = 11
65
The number 1111115
1 + 1 = 2 The sum of the digits is therefore 2.
The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.
The difference betweenthe sum of the digits in odd positions andthe sum of the digits in even positionsis divisible by 11.
65
22
65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11
By the sum of its digits: 10. By each of its individual digits: 11.
How about 65 because 6+5 = 11
65
Sum the digits in the odd positions in the integer. Sum = XSum the digits in the even positions in the integer. Sum = YIf X - Y is a multiple (including negative or 0), then the given integer is divisible by 11.
11
The number 1111115