The integers are 12 and 14
(144+196=340)
9,11,13
The positive square root of 64 is exactly equal to 8.
The square root of 148 is not an integer.
The square of a positive number is positive. By the way, the square of a negative number is also positive.
As integers are numbers that are whole, 4.8 is not an integer.
9,11,13
Only if the integer is a perfect square.
The numbers are 3, and 4.
Try squaring different integers (hint: in this case, the integers will be fairly small). If you find that the square of one integer is less than 27, and the square of the next integer is more than 27, you have your answer.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
No, it is not possible.
The positive square root of 64 is exactly equal to 8.
The square root of 137 is not an integer and so does not.
A square number is the product of the same two integers. A rectangular number is the product of consecutive integers.
If you have two consecutive integers then one of them must be odd and the other must be even. The square of an odd integer must be odd, the square of an even integer must be even. The sum of an odd number and an even number must be odd. Thus, the sum of squares of any two consecutive numbers must be odd. Therefore, the question has no valid answer.
two consecutive integers of the square root of 66 found between
The square roots of 117 are irrational numbers and so are not two integers - consecutive or otherwise.