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The sum of three consecutive integers is sixteen less than five times the middle integer Find the middle integer?
Wiki User
∙ 14y ago
a+(a+1)+(a+2) = (a+1)-16
3a+3 = a-15
2a = -18
a = -9
(a+1) = -8
The middle integer is -8.
Wiki User
∙ 14y ago
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Find three consecutive integers such that three times the middle integer is one more than the sum of the first and third?
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
What are three consecutive integers of -363?
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
What are the 4 consecutive odd integers where the sum of the middle two integers is equal to 24?
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
Find three consecutive odd integers such that three times the middle integer is one more than the sum of the first and third?
-1, 1 and 3
What is three consecutive even integers whose sum equals 210?
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
The sum of the three consecutive integers?
The sum of three consecutive integers is -72
Find three positive consecutive odd integers such that the square of the middle integer increased by four times the largest integer is 173?
9,11,13
Find three consecutive integers such that three times the middle integer is one more than the sum of the first and third?
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
3 consecutive integeres whose sum is 93?
Middle integer must be a third of 93 so integers are 30, 31 and 32.
What are three consecutive integers of -363?
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
What are the 4 consecutive odd integers where the sum of the middle two integers is equal to 24?
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
Find three consecutive odd integers such that three times the middle integer is one more than the sum of the first and third?
-1, 1 and 3
There are 3 consecutive integers 3 times the largest is 7 times the smallest what are the integers?
Let x be the middle integer: 3(x+1) = 7(x-1) 3x + 3 = 7x - 7 3x + 10 = 7x 10 = 4x So the middle one is 10/4 which is not an integer. So there is really no solution.
What is three consecutive even integers whose sum equals 210?
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
How do you solve a consecutive integer?
The following is an example of consecutive integer problems.Example 1: Consecutive Integer ProblemThe sum of the least and greatest of 3 consecutive integers is 60. What are the values of the 3 integers?Solution:Step 1: Assign variables : Let x = least integer x+ 1 = middle integer x + 2 = greatest integerTranslate sentence into an equation.Sentence: The sum of the least and greatest is 60.Rewrite sentence: x + (x + 2) = 60Step 2: Solve the equationCombine like terms 2x + 2 = 60Isolate variable x2x =58Step 3: Check your answer 29 + 29 + 2 = 60The question wants all the 3 consecutive numbers: 29, 30 and 31Answer: The 3 consecutive numbers are 29, 30 and 31.pato c napano
What is the product of 15 consecutive integers whose average is7?
I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.
The sum of three consecutive integers is 135 What is the greatest of the three integers?
Given the sum of three consecutive integers 135, we write out the expression as:x + (x + 1) + (x + 2) = 135 where:x = smallest integerx + 1 = middle integerx + 2 = largest integerSolve for x by rearranging the terms:3x + 3 = 1353x = 132x = 44Therefore, the largest integer is x + 2 = 46.
