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Given the sum of three consecutive integers 135, we write out the expression as:

x + (x + 1) + (x + 2) = 135 where:

  • x = smallest integer
  • x + 1 = middle integer
  • x + 2 = largest integer

Solve for x by rearranging the terms:

3x + 3 = 135

3x = 132

x = 44

Therefore, the largest integer is x + 2 = 46.

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Q: The sum of three consecutive integers is 135 What is the greatest of the three integers?
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Find three consecutive odd integers whose sum is 135?

Those three odd integers are 43, 45, and 47.


Three consecutive integers whose sum is 135?

Let's call the three consecutive integers x, x+1, and x+2. The sum of these integers is x + (x+1) + (x+2) = 3x + 3. We know that this sum is equal to 135, so we can set up the equation 3x + 3 = 135. Solving for x gives us x = 44. Therefore, the three consecutive integers are 44, 45, and 46.


Three consecutive numbers have a sum of 135?

44,45,46


What three consecutive numbers total 135?

44,45,46


Three consecutive numbers have the sum of 135 what are the numbers?

44 + 45 + 46 = 135


Three consecutive numbers have a sum of 135 what are the numbers?

44 + 45 + 46 = 135


What is the greatest common multiple of 81 and 135?

The greatest common multiple of any set of integers is infinite.


What is the greatest common multiple of 102 135 and 204?

The greatest common multiple of any set of integers is infinite.


What are three consecutive odd integers whose sum is 135?

43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47


What Three consecutive numbers total 135 what are the numbers?

let the three consecutive no.s be k-1,k and k+1,where k is a positive whole no. so (k-1)+k+(k+1)=135 according to the question or, 3k=135 or, k=45 which gives the no.s as 44,45,46 44+45+46=135


What is the greatst divisor of 135?

135 is the greatest divisor of 135.


Five times the sum of three consecutive integers is 150 what are the integers?

Let x=1st integer x+1=2nd integer x+2=3rd integer 5(x+x+1+x+2)=150 5(3x+3)=150 15x+15=150 15x=135 x=9 So you put what x is 1st integer (x)= 9 Since it's three consecutive integers, you add one to the 2nd integer 2nd integer (x+1)= 10 Then you do the same thing for the third integer 3rd integer (x+2)= 11