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Q: The sum of three consecutive integers is 135 What is the greatest of the three integers?

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44,45,46

43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47

135 is the greatest divisor of 135.

The Greatest Common Divisor of 135, 125 is 5.

135 and 136.

Related questions

The integers are 44, 45 and 46.

Those three odd integers are 43, 45, and 47.

44,45,46

44,45,46

44 + 45 + 46 = 135

44 + 45 + 46 = 135

The greatest common multiple of any set of integers is infinite.

The greatest common multiple of any set of integers is infinite.

43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47

let the three consecutive no.s be k-1,k and k+1,where k is a positive whole no. so (k-1)+k+(k+1)=135 according to the question or, 3k=135 or, k=45 which gives the no.s as 44,45,46 44+45+46=135

45, 90 and 135

135 is the greatest divisor of 135.

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