Given the sum of three consecutive integers 135, we write out the expression as:
x + (x + 1) + (x + 2) = 135 where:
Solve for x by rearranging the terms:
3x + 3 = 135
3x = 132
x = 44
Therefore, the largest integer is x + 2 = 46.
44,45,46
43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47
135 is the greatest divisor of 135.
The Greatest Common Divisor of 135, 125 is 5.
135 and 136.
The integers are 44, 45 and 46.
Those three odd integers are 43, 45, and 47.
44,45,46
44,45,46
44 + 45 + 46 = 135
44 + 45 + 46 = 135
The greatest common multiple of any set of integers is infinite.
The greatest common multiple of any set of integers is infinite.
43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47
let the three consecutive no.s be k-1,k and k+1,where k is a positive whole no. so (k-1)+k+(k+1)=135 according to the question or, 3k=135 or, k=45 which gives the no.s as 44,45,46 44+45+46=135
45, 90 and 135
135 is the greatest divisor of 135.