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Q: The sum of two consecutive even integers is 118?

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There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.

The numbers are -18, -16 and -14.

The three integers are 25, 26, and 27.

65, 66, 67

-11, -10, -9

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There are two consecutive even integers. The numbers are 118 and 120.

118

116 + 118 = 234. Answer is 118. Took 5 seconds to do.

No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.

There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.

The average must be 360/3 ie 120 so the integers are 118, 120 and 122.

The two consecutive, even integers are 350 and 352.

No two consecutive even integers satisfy that request.

No. There is no set of three consecutive even integers with a sum of 40.

Half it = 41, so consecutive even integers are 40 & 42

The smallest of seven consecutive even integers whose sum is 700 is 94.

This question cannot be answered. There are no two consecutive even integers that yield the sum of 60.

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