Nanie5
116 + 118 = 234. Answer is 118. Took 5 seconds to do.
Wiki User
∙ 14y agoAn even integer is a number that is a multiple of 2. If n is an even integer, the next consecutive even integers are n+2, n+4 and so on.
The first integer is 17.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
n-3
There are only 3 sets of consecutive even integers less than 12, you can work it out...
The larger integer is 30. The smaller is 28.
An even integer is a number that is a multiple of 2. If n is an even integer, the next consecutive even integers are n+2, n+4 and so on.
The first integer is 17.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114
28,30
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The integers are 20 and 22.
There are not two consecutive odd integers. An integer is a whole number and consecutive is something that follows continuously/unbroken, logical sequence. All odd integers will have an even integer in between: 1, 2, 3, 4, 5...
n-3
There are only 3 sets of consecutive even integers less than 12, you can work it out...
No two consecutive EVEN integers sum to 124 since: Let x be the lowest of the two integers. Then the other integer is x+2 and x + (x+2) = 124 iff 2x = 122 iff x=61, an odd integer.