114.
As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:
Where x is the smaller number,
x + (x + 2) = 226
2x + 2 = 226
2x = 224
x = 112
Therefore the larger integer is 112 + 2 = 114
The larger is 114, and the other is 112.
No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.
The numbers are 14, 16 and 18.
Half it = 41, so consecutive even integers are 40 & 42
There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .
The larger integer is 30. The smaller is 28.
An even integer is a number that is a multiple of 2. If n is an even integer, the next consecutive even integers are n+2, n+4 and so on.
The first integer is 17.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
116 + 118 = 234. Answer is 118. Took 5 seconds to do.
28,30
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The integers are 20 and 22.
n-3
There are not two consecutive odd integers. An integer is a whole number and consecutive is something that follows continuously/unbroken, logical sequence. All odd integers will have an even integer in between: 1, 2, 3, 4, 5...
There are only 3 sets of consecutive even integers less than 12, you can work it out...
-148 and -150an integer is a whole number, no decimal places