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What is the larger of two consecutive even integers if their sum is 226?
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∙ 7y ago
The larger is 114, and the other is 112.
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∙ 7y ago
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The sum of two consecutive even integers is 226 What is the larger integer?
114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114
What are two consecutive odd integers that multiply up to 225?
13 x 15 = 195 . . . too small15 x 17 = 255 . . . too bigThere are none.The best we can do for you is: (14 x 16) = 224 .===================================For the advanced student:If you work it from the generic form of two consecutive odd numbers,then you would say(2x - 1) (2x + 1) = 225Whence . . . (4x2 - 1) = 225 . . . 4x2=226 . . . x2=56.5 . . . x=sqrt(56.5)The two numbers are 14.0333 and 16.0333 . (rounded)A truly revolting development. Although their product is nice and close to 225,there's no way you could pass them off as odd integers.
What equals 226?
113 x 2 is 226
What times what equals 420?
The numbers below are the factor pairs of 420 (multiplied together they equal 420) (1, 420) (2, 210) (3, 140) (4, 105) (5, 84) (6, 70) (7, 60) (10, 42) (12, 35) (14, 30) (15, 28) (20, 21)
How do you count by 6's?
6,12, 18, 24, 30, 36,42,48, 54, 60, 66, 72, 78, 84, 90, 96, 102, 108, 114, 120, 126, 132, 138, 144, 150, 156, 162, 178, 184, 190, 196, 202, 208, 214, 220, 226, 232, 238, 244, 250, 256, 262, 268, 274, 280, 286, 292, 298 etc.
Find two consecutive even integers that have a sum of 450?
224 and 226
The sum of two consecutive even integers is 226 What is the larger integer?
114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114
Find two consecutive even numbers whose product is 50624?
224 x 226
What are three consecutive numbers of 681?
The numbers are 226, 227 and 228.
Is 226 a even number?
Yes, it is.
What is Harrison Ford's IQ?
larger than mine roy marzano
What is the sum of the first 113 consecutive even numbers?
It should be 12882 if I calculated correctly. However I cannot show you how I got the answer here because of the limited mathematical symbols input here. The steps involve using sigma with upper and lower limits. If you want to see my work, visit quickanswerz.com and post this same question there and I can show you exactly how it's worked out!The even number starts with 2 and goes on.2, 4, 6, 8… It forms a sequence with the first term 'a' is 2 and the common difference 'd' is 2. We need to find the sum of the first 113 consecutive even numbers. Sum of n terms in a sequence is given by the formula Sn = (n/2) (a + l) (Where 'a' is the first term of the sequence and 'l' is the last term of the sequence.) First, we need to find the last term of the sequence. We know that the nth term of a sequence is given by the formula tn = a + (n-1) d So, t113 = a + (113-1) d. Substitute the value of a and d in the above equation. t113 = 2 + (113-1) 2 = 2 + (112) 2 t113 = 2 + 224. t113 = 226. So, the last term l is 226. Now, substitute all the values in the formula Sn = (n/2) (a + l). Sn = (113/2) (2 + 226) Sn = (113/2) (228) Sn = (113) (114) Sn = 12882 So, the sum of the first 113 consecutive integers is 12882. Source: www.icoachmath.com Option 2 An easier solution would be to use the formula N(N+1), where N is the number of consecutive even numbers. Eg: sum of 113 consecutive even integers would be = 113* 114 = 12882. Use this formula to calculate the sum of consecutive even numbers starting from 2. If the number starts from the middle (20,22,24,26) you need to use Option 1 to find the solution.
What are two consecutive odd integers that multiply up to 225?
13 x 15 = 195 . . . too small15 x 17 = 255 . . . too bigThere are none.The best we can do for you is: (14 x 16) = 224 .===================================For the advanced student:If you work it from the generic form of two consecutive odd numbers,then you would say(2x - 1) (2x + 1) = 225Whence . . . (4x2 - 1) = 225 . . . 4x2=226 . . . x2=56.5 . . . x=sqrt(56.5)The two numbers are 14.0333 and 16.0333 . (rounded)A truly revolting development. Although their product is nice and close to 225,there's no way you could pass them off as odd integers.
What are the first five multiples of 226?
226 x 1 = 226 226 x 2 = 452 226 x 3 = 678 226 x 4 = 904 226 x 5 = 1130 226 x 6 = 1356
The sum of three consecutive natural numbers is 681 find the numbers?
The middle number must be the average, so 681/3 = 227 and the other two numbers are 226 and 228.
What is the cube of 226?
The cube is raised to the power of 3, or 226 x 226 x 226 = 11543176.
What is the prime factor tree of 226?
226 2,113
