The larger is 114, and the other is 112.
114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114
13 x 15 = 195 . . . too small15 x 17 = 255 . . . too bigThere are none.The best we can do for you is: (14 x 16) = 224 .===================================For the advanced student:If you work it from the generic form of two consecutive odd numbers,then you would say(2x - 1) (2x + 1) = 225Whence . . . (4x2 - 1) = 225 . . . 4x2=226 . . . x2=56.5 . . . x=sqrt(56.5)The two numbers are 14.0333 and 16.0333 . (rounded)A truly revolting development. Although their product is nice and close to 225,there's no way you could pass them off as odd integers.
113 x 2 is 226
6,12, 18, 24, 30, 36,42,48, 54, 60, 66, 72, 78, 84, 90, 96, 102, 108, 114, 120, 126, 132, 138, 144, 150, 156, 162, 178, 184, 190, 196, 202, 208, 214, 220, 226, 232, 238, 244, 250, 256, 262, 268, 274, 280, 286, 292, 298 etc.
I assume that you're talking about surface area. If so, imagine making a cylinder out of paper. You would have two circles, and between them a rectangle rolled up, right? So let's address the circles first. If the radius is 6 cm, then each circle's area (pi x radius squared) is: pi x (6 x 6) = 36pi = 113 sq cm Now we need to address the rectangle. Picture unrolling it. We would have a rectangle with a height of 5 cm and a length equal to the circumference of the base, right? So figure out the circumference. It (pi x D) is: pi x (2 x 6) = 12pi = 37.7 cm The area of the rectangle (base x height) is: 37.7 x 5 = 188.5 sq cm So, to get the total surface area, we add the rectangle (188.5 cm) and the TWO bases (113 sq cm x 2 = 226 sq cm), or 188.5 + 226 = 414.5 sq cm, rounded to the nearest, 415 sq cm
224 and 226
114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114
224 x 226
The numbers are 226, 227 and 228.
Yes, it is.
larger than mine roy marzano
It should be 12882 if I calculated correctly. However I cannot show you how I got the answer here because of the limited mathematical symbols input here. The steps involve using sigma with upper and lower limits. If you want to see my work, visit quickanswerz.com and post this same question there and I can show you exactly how it's worked out!The even number starts with 2 and goes on.2, 4, 6, 8… It forms a sequence with the first term 'a' is 2 and the common difference 'd' is 2. We need to find the sum of the first 113 consecutive even numbers. Sum of n terms in a sequence is given by the formula Sn = (n/2) (a + l) (Where 'a' is the first term of the sequence and 'l' is the last term of the sequence.) First, we need to find the last term of the sequence. We know that the nth term of a sequence is given by the formula tn = a + (n-1) d So, t113 = a + (113-1) d. Substitute the value of a and d in the above equation. t113 = 2 + (113-1) 2 = 2 + (112) 2 t113 = 2 + 224. t113 = 226. So, the last term l is 226. Now, substitute all the values in the formula Sn = (n/2) (a + l). Sn = (113/2) (2 + 226) Sn = (113/2) (228) Sn = (113) (114) Sn = 12882 So, the sum of the first 113 consecutive integers is 12882. Source: www.icoachmath.com Option 2 An easier solution would be to use the formula N(N+1), where N is the number of consecutive even numbers. Eg: sum of 113 consecutive even integers would be = 113* 114 = 12882. Use this formula to calculate the sum of consecutive even numbers starting from 2. If the number starts from the middle (20,22,24,26) you need to use Option 1 to find the solution.
13 x 15 = 195 . . . too small15 x 17 = 255 . . . too bigThere are none.The best we can do for you is: (14 x 16) = 224 .===================================For the advanced student:If you work it from the generic form of two consecutive odd numbers,then you would say(2x - 1) (2x + 1) = 225Whence . . . (4x2 - 1) = 225 . . . 4x2=226 . . . x2=56.5 . . . x=sqrt(56.5)The two numbers are 14.0333 and 16.0333 . (rounded)A truly revolting development. Although their product is nice and close to 225,there's no way you could pass them off as odd integers.
The result of subtracting 455 from 229 is -226. This is because when subtracting a larger number from a smaller number, we end up with a negative result. In this case, the absolute difference between the two numbers is 226, and the negative sign indicates that 455 is greater than 229.
226 x 1 = 226 226 x 2 = 452 226 x 3 = 678 226 x 4 = 904 226 x 5 = 1130 226 x 6 = 1356
The middle number must be the average, so 681/3 = 227 and the other two numbers are 226 and 228.
113 x 2 is 226