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The sum of two consecutive integers is 15?
Let the first integer be x. The second consecutive integer would then be x+1. The sum of these two integers is x + (x+1) = 15. Simplifying, we get 2x + 1 = 15. Solving for x, we find that x = 7. Therefore, the two consecutive integers are 7 and 8.
How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
The sum of two consecutive positive integers is less than or equal to 10 Find the integers.?
Let the first integer be x, and the second one be x + 1. So we have: x + x + 1 ≤ 10 2x + 1 ≤ 10 subtract 1 from both sides 2x ≤ 9 divide by 2 to both sides x ≤ 9/2 x ≤ 4.5 Since the numbers are integers, the largest number x may be 4, and the largest second number may be 5. Thus, the numbers are: First integer ≤ 4 and second integer ≤ 5.
If the sum of the first two of the five consecutive odd integers is 52what is the sum of the last two integers?
Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).
Find 3 consecutive odd integers as you know that the sum of the smallest odd integer and the middle integer is equal to 8 times the largest odd integer?
Let the smallest consecutive odd integer be x, so the second will be x + 2, and the third one be x + 4. So we have:x + (x + 2) = 8(x + 4)2x + 2 = 8x + 322x - 8x + 2 - 2 = 8x - 8x + 32 - 2-6x = 30-6x/-6 = 30/-6x = -5 (the first odd integer)x + 2 = -5 + 2 = -3 (the second)x + 4 = -5 + 4 = -1 (the third)Thus, the three consecutive odd integers are -5, -3, and -1.Check:
The sum of 3 consecutive even integers is 54 What is the first consecutive integer?
The first integer is 17.
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
What is the equation for this The sum of two consecutive integers in 71?
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
When you double the first and quadruple the second integer their sum is 30 find the consecutive integers?
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
Find 2 consecutive integers whose difference is 2?
no solution. If you solve for x (where x is the first integer) the answer is a fraction, which is not an integer.
The sum of two consecutive integers is 15?
Let the first integer be x. The second consecutive integer would then be x+1. The sum of these two integers is x + (x+1) = 15. Simplifying, we get 2x + 1 = 15. Solving for x, we find that x = 7. Therefore, the two consecutive integers are 7 and 8.
What is the sum of four consecutive even integers is 2 more than five times the first integer?
The integers would begin with 10.
How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
