Top Answer

43 is the sum of the two consecutive integers 21 and 22.

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2They are 21 and 22

The numbers are 43 and 45.

There are none.

The integers are are 41, 42 and 43.

129 divided by 3 is 43, so the 3 consecutive integers having a sum of 129 are 42, 43, and 44.

There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.

The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.

41+42+43=126.

The numbers are 41, 43 and 45.

40, 41, 42, and 43 are.

It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16

123/3 = 41 so integers are 39, 41 and 43

It is 42 because 42+43+44 = 129

The numbers are 39, 41 and 43.

They are: -39 -41 -43 = -123

Those three odd integers are 43, 45, and 47.

132/3 = 44 43, 44, 45

2 times 30+31+32+33 41+42+43

The integers are 43 and 44. The answer can be found by representing the two consecutive numbers as "n" and "n+1". n2 + (n+1)2 = 3785 n2 + (n2 + 2n + 1) = 3785 2n2 + 2n + 1 = 3785 2n2 + 2n - 3784 = 0 n2 + n - 1892 = 0 (n + 44) (n-43) = 0 n = -44, +43 The answer is restricted to positive values, so n = 43 and n+1 = 44

The numbers are 43 and 45.

The four consecutive odd integers are 43 + 45 + 47 + 49 = 184

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