Find 2 consecutive ODD integers whose sum is -88
ANSWER:
-45, -43
Aaron.
Wiki User
∙ 9y agoThere is no set of three consecutive integers whose sum is 88.
258/3 = 86 so the answer has to be 84+86+88
88,89,90 the answer is 88, 89,90.
82, 84, 86, 88
The numbers are -25, -23, -21 and -19.
Since 270 is an even number, then three consecutive odd numbers cannot add to 270. ,because Odd + odd = even (2 numbers_ Even + odd = odd ( plus a third number) odd + odd = even (plus a fourth number) even + odd = odd (plus a fifth number) Notice from the table that the third odd number gives an odd answer; not an even answer. e.g. three odd numbers 3,5, & 7. 3 + 5 = 8 (even) 8 + 7 = 15 ( odd) et. seq.,
258/3 = 86 so the answer has to be 84+86+88
They are 88 and 89.
88,89,90 the answer is 88, 89,90.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
The numbers are 43 and 45.
The numbers are 82, 84, 86 and 88.
-45 and -43.
82, 84, 86, 88
The numbers are -25, -23, -21 and -19.
Algebraically, X = integer. X + (X + 1) = 89 2X + 1 = 89 2X = 88 X = 44 ------------so X + 1 which is 44 + 1 = 45 ( 44, 45) --------------are your consecutive integers
Two positive integers cannot have a sum which is negative!
I assume you wish to know which four consecutive even integers sum to 340. Let the smallest of the integers be x. Then the others are x+2, x+4 and x+6 and x + (x+2) + (x+4) + (x+6) = 340 iff 4x = 328 iff x = 82. So the integers are 82, 84, 86 and 88.