Let n = smallest of the odd numbers, then let n+2 = the larger of the two numbers (Remember, 1 is not a Prime number.) n+ n+2 = {(2)(7)}2 2n +2 = 142 2n = 196 -2 2n = 194 n = 97 n + 2 = 99
The square root of 47 lies between the consecutive whole numbers 6 and 7.
They are 9 times 16 = 144
It is: 12 and 13
There are none. However, there are two consecutive positive odd numbers: 25 and 27.
The answer would be 5 and 6
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
5,6,7
11,12,13
5.385 is the square root of 29. No consecutive numbers.
The numbers are 88 and 89 (88 x 89 = 7,832). This is very easy to find. The products you are looking for are consecutive and so they are very close to each other. Calculate the square root of the number, and it is easy to see that if there are two consecutive whole numbers that will be products of the number, they will be consecutive whole numbers very close to the square root. The square root of 7832 is about 88.5.
8,10,12
1, 3, 5
16, 17 and 18
12, 13 and 14
8, 9, and 10
5, 6 and 7