45
Sum = 109 Difference = 89
1002 and -1000 Does that count?
What is the sum of greatest 3-digit 4-digit 5digit
The number is 949.
sum
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
None. The sum of one digit can't be twice the size of the digit.
The final sum is 9
class ass{ public static void main(String[] args ){ int 13,33,23,...193 sum = 0; for (count = 0; count<=193; count++); { sum=sum+count; System.out.print(count + "sum"); }System.out.println("sum is"+sum);
9
45 if you don't count numbers that start with a zero, such as 000 or 011. If you do count them it would be 55. You have 9 that start with 1 as their first digit since the lowest possible sum is 1 (101) and the highest possible sum which can fit in one digit is 9 (189). You have 8 that start with "2" since the lowest possible sum is 2 (202) and the highest possible sum will always be 9 (279). You have 7 that start with 3 since the lowest possible sum is 3 (303) and the highest possible sum is 9 (369) and so on until you get to numbers that start with 9 of which there is only one, 909. So, you have 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45. If you count zero as a possible first digit then you can add ten because there's ten that start with zero.
i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i