The sum of two numbers is a whole number if both of the numbers are whole numbers, or if the sum of two fractions can be simplified to a whole number.
It is not clear what the question means: there are 31 2-digit numbers that can be expressed as a sum of two squares.
Highest 2-digit number = 99 Highest 1-digit number = 9 Highest possible sum from 2, 2-digit numbers = 198 Highest possible sum from 2, 1-digit numbers = 18
The 3 largest 2 digit prime numbers are 83, 89, and 97. The sum is 269
Oh, dude, you want me to find 4-digit numbers where the digits add up to 2? That's like finding a needle in a haystack! But hey, I'm up for the challenge. The only number that fits the bill is 1001. So, there you go, one lonely 4-digit number with a digit sum of 2.
The sum of two numbers is a whole number if both of the numbers are whole numbers, or if the sum of two fractions can be simplified to a whole number.
It is not clear what the question means: there are 31 2-digit numbers that can be expressed as a sum of two squares.
Highest 2-digit number = 99 Highest 1-digit number = 9 Highest possible sum from 2, 2-digit numbers = 198 Highest possible sum from 2, 1-digit numbers = 18
The 3 largest 2 digit prime numbers are 83, 89, and 97. The sum is 269
21
Oh, dude, you want me to find 4-digit numbers where the digits add up to 2? That's like finding a needle in a haystack! But hey, I'm up for the challenge. The only number that fits the bill is 1001. So, there you go, one lonely 4-digit number with a digit sum of 2.
For a 2-digit prime number (which are all odd) to be the sum of two prime numbers, one of the prime numbers will have to be 2. That means the difference between the sum and the other addend will have to be 2. Prime numbers that differ by 2 are called twin primes. There are six pairs of 2-digit twin primes. Your numbers are 13, 19, 31, 43, 61 and 73.
You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m
IN WHOLE NUMBER FIRST DIGIT IS 0 SO THAT WE HAVE TO SUM 1-98 NUMBERS :-SUM OF 1-10 IS 55 SO IN SUM OF EACH 11-20,21-30......THE UNIT DIGIT WILL COME 5 SO FOR THAT WE MULTIPLY 5*9+1+2+3+4+5+6+7+8 AFTER THIS CALCULATION WE GOT 1 AS A UNIT DIGIT NUMBER
198
19, 998.
14, 32, and 50