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I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.
They are equal.
Derive from measurements of length, breadth, height, radius, diameter etc. Measure the volume of displaced liquid when the object is submerged. If the object is of a material of known density (or specific gravity), weigh it and calculate volume from volume = mass/density.
Length times Width times Height. Archimedes used a "bathtub", and submerged the object to see what volume of water was displaced.
If the object is irregular you have no hope of calculating its volume from any known dimensions. The easiest way to find its volume is to fill a container full of a liquid (with which the object will not react). Submerge the object in the liquid and collect the liquid displaced. The volume of the displaced liquid, which should be easily measurable, will be the same as that of the object.