4/7 or a 57.14% chance
Probability of getting not a yellow sweet if there 3 yellow sweets and 10 blue sweets is 10/13.
Step 1: Count the total number of sweets in a "bag"There are 3 yellow, 5 green, 7 red, 4 purple and 1 black sweets. Add all these values up to obtain 20 sweets total.Step 2: Determine the probability of the given eventSince we want to determine the probability of selecting a black sweet out of a "bag", we have:1 / 20 = number of black sweets / total number of sweets
3/4
3/16
If the balls are selected at random, then the probability is 12/95.
Three sixteenths, or 19%.
27/64
To find the probability of picking a yellow card first and then a blue card second without replacement, you need to know the total number of yellow and blue cards in the deck. Assuming there are (Y) yellow cards and (B) blue cards in a total of (T) cards, the probability is calculated as (P(yellow) \times P(blue | yellow)). This simplifies to (\frac{Y}{T} \times \frac{B}{T-1}). The final answer will depend on the specific values of (Y), (B), and (T).
What is the probability that the second tile you pick is yellow? (didnt have enough space to finish the question)
The answer depends on how many are picked,whether they are returned after picking and whether the picking is done at random. In a single random selection the probability is 17/25.
11/16
5/12