There is a 1/13 chance of getting an L. There is a 2/13 chance of getting an I. There is a 3/13 chance of getting an E. There is a 1/13 chance of getting a C. There is a 2/13 chance of getting a T. There is a 2/13 chance of getting a N. There is a 1/13 chance of getting an S. There is a 1/13 chance of getting an H.
Very low (less than 0.00000000001%)
Red cards will be a 1/3 chance to pick out of three cards .
52 cards, 4 of them 3s... 4 in 52 = 1 in 13 = ~7.7%
It is 16/52 = 4/13
About a 3.8% chance (2 / 52 = 0.038...).
The probability of the occurrence of a deck of cards is 1.
The probability of drawing a queen or king, in a single randomly drawn card, is 2/13. The probability of drawing one when you draw 45 cards without replacement is 1. The probability of choosing has nothing t do with the probability of drawing the card. I can choose a king but fail to find one!
It is (26*25)/(52*51) = 650/2652 = 0.2451
For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.
Oh, dude, you're talking about a standard deck of 52 cards, right? So, like, there are 26 red cards and 26 black cards in there. If you're picking 4 cards randomly, the probability of getting 2 red and 2 black suits would be calculated by like, dividing the number of ways you can choose 2 red and 2 black cards by the total number of ways to choose 4 cards from 52. It's like a math problem, but with cards, man.
Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52
If you draw 9 or fewer cards, the probability is 0. If you draw 10 or more card, the probability is 1.