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There are 6 brown 5 blue and 2 orange marbles in a hat. What is the probability of picking two orange marbles in a row without returning the marbles back to the hat?
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A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
What is the probability of 6 green marbles?
We can't answer that without knowing what else is in the bowl.
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
What is the probability of 6 green marbles?
We can't answer that without knowing what else is in the bowl.
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
A bag contains 5 green marbles 3 yellow and 2 red marbles. What is the probability of picking three green marbles from the bag without replacement?
To find the answer to probability, first add all the things together (5+3+2=10), then, find the number of things you will be taking from the group of things (3), and put together as a fraction (3/10). So the final answer is 3/10, which is unlikely. :D
In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
You have 12 marbles 8 are blue 4 are green what is probability one of each color is chosen on the first two draws?
If the two marbles are drawn without replacement, the probability is 16/33.
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
What is the probability that at least one marble is white if a bag has 3 green and 3 white marbles four marbles are selected at the same time?
The probability is 100%.There's no way to take four marbles out of this bag without at least one of them being white.
What is the probability of chossing 12 marbles from a jar in numercial order?
The probability of picking the #1 marble on the first draw is 1/12. If you've done that, then the probability of picking the #2 marble on the second draw is 1/11. If you've done that, then, the probability of picking the #3 marble on the third draw is 1/10. If you've done that, then, the probability of picking the #4 marble on the fourth draw is 1/11. etc. etc. So the probability of doing all of them in sequence is (1/12) x (1/11) x . . . x (1/1). That's exactly the reciprocal of (12!). According to my $1.49 calculator, your chances of success without peeking amount to about 0.00000020877 percent (rounded) Not a smart bet.
A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?
sure chance
If you pick two marbles without replacing the first (g4 r2 y3) what is P(red then green)?
The probability is 1/9.
