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The probability is 1/9.

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Q: If you pick two marbles without replacing the first (g4 r2 y3) what is P(red then green)?
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A bag contains 3 red marbles 2 blue marbles and 5 green marbles What is the probability of selecting a red marble without replacing it in the bag and then selecting a green marble?

Total marbles in the bag = 10Number of red ones = 3Probability of pulling a red one on the first draw = 3/10 = 0.3Total marbles remaining after the first draw = 9Number of green ones = 5Probability of pulling a green one after a red one has been withdrawn = 5/9Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent.


A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?

Because you are replacing the marbles then it is an independent event. P(1st one is not green) = 1 - P(first green), equally P(2nd one is not green) = 1 - (second green), Thus it reads P(¬G ^ ¬G) = P(¬G) * P(¬G) = 15/20 * 15/20 = 225/400 = 9/16


Erry has a total of 23 marbles The marbles are either blue or green He has three more blue marbles than green marbles How many green marbles does he have?

He has 10 green marbles.


Jerry has a total of 23 marbles the marbles are either blue or green he has three more blue marbles than green marbles how many marbles does he have?

He will have 13 blue marbles and 10 green marbles.


You have 12 marbles 8 are blue 4 are green what is probability one of each color is chosen on the first two draws?

If the two marbles are drawn without replacement, the probability is 16/33.


Jerry has a total of 23 marbles The marbles are either blue or green He has three more blue marbles than green marbles How many blue marbles does he have?

10 Green marbles, 13 Blue marbles.


If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?

4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.


In a bag of 7 black marble 8 red marbles and 6 green marbles what is the least number of marbles you must pick without looking to guarantee two marbles of the same color?

== ==


A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?

sure chance


A bag of marbles has twice as many blue marbles as green and the bag has at least 33 marbles in it at least how many green marbles are in the bag?

There are at least 11 green marbles in the bag.


What is the probability of 6 green marbles?

We can't answer that without knowing what else is in the bowl.


What is the probability that blue will be first there are 8 red marbles 2 blue marbles 7 yellow marbles and 3 green?

1 chance in 10.10 %