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A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?
To calculate the probability of not drawing two green marbles, we first find the probability of drawing a green marble on the first draw, which is 5/20 since there are 5 green marbles out of a total of 20 marbles. The probability of not drawing a green marble on the first draw is 1 - 5/20 = 15/20. Since the marbles are replaced, the probability of not drawing a green marble on the second draw is also 15/20. Therefore, the probability of not drawing two green marbles is (15/20) * (15/20) = 225/400 = 9/16 or 56.25%.
You have 12 marbles 8 are blue 4 are green what is probability one of each color is chosen on the first two draws?
If the two marbles are drawn without replacement, the probability is 16/33.
In a bag of 7 black marble 8 red marbles and 6 green marbles what is the least number of marbles you must pick without looking to guarantee two marbles of the same color?
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In a bag there are 8 red marbles 4 blue marbles and 6 green marbles write the ratio of red marbles to green marbles?
8:6
What is the probability of pulling out a red marble then a blue marble without replacing the red marble the bag contains 3 red marbles 2 blue marbles and 5 green marbles?
1 out of 15 Probab. = Prob. of red x Prob. of blue Probab. = (3/10)x(2/9) = 5/90 = 1/15
What is the probability of not drawing a green marble?
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
A bag contains 3 red marbles 2 blue marbles and 5 green marbles What is the probability of selecting a red marble without replacing it in the bag and then selecting a green marble?
Total marbles in the bag = 10Number of red ones = 3Probability of pulling a red one on the first draw = 3/10 = 0.3Total marbles remaining after the first draw = 9Number of green ones = 5Probability of pulling a green one after a red one has been withdrawn = 5/9Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent.
A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?
To calculate the probability of not drawing two green marbles, we first find the probability of drawing a green marble on the first draw, which is 5/20 since there are 5 green marbles out of a total of 20 marbles. The probability of not drawing a green marble on the first draw is 1 - 5/20 = 15/20. Since the marbles are replaced, the probability of not drawing a green marble on the second draw is also 15/20. Therefore, the probability of not drawing two green marbles is (15/20) * (15/20) = 225/400 = 9/16 or 56.25%.
Erry has a total of 23 marbles The marbles are either blue or green He has three more blue marbles than green marbles How many green marbles does he have?
He has 10 green marbles.
Jerry has a total of 23 marbles the marbles are either blue or green he has three more blue marbles than green marbles how many marbles does he have?
He will have 13 blue marbles and 10 green marbles.
You have 12 marbles 8 are blue 4 are green what is probability one of each color is chosen on the first two draws?
If the two marbles are drawn without replacement, the probability is 16/33.
Jerry has a total of 23 marbles The marbles are either blue or green He has three more blue marbles than green marbles How many blue marbles does he have?
10 Green marbles, 13 Blue marbles.
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
In a bag of 7 black marble 8 red marbles and 6 green marbles what is the least number of marbles you must pick without looking to guarantee two marbles of the same color?
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A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?
sure chance
A bag of marbles has twice as many blue marbles as green and the bag has at least 33 marbles in it at least how many green marbles are in the bag?
There are at least 11 green marbles in the bag.
What is the probability of 6 green marbles?
We can't answer that without knowing what else is in the bowl.
