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Three consecutive numbers are x, (x+1), (x+2).

x + (x+1) + (x+2) = 3x + 3 = 126

3x = 123

x = 123/3 = 41

The numbers are 41, 42, 43.

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โˆ™ 2009-08-26 15:15:12
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Q: Three consecutive numbers that have the sum of 126?
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