41, 42 and 43
The two even consecutive integers are: 62+64 = 126
41, 42 and 43
41+42+43=126.
The integers are are 41, 42 and 43.
41,42,43
63+83=126.... hope it helps!
41+42+43 = 126
There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.
The numbers are 62 and 64 are two consecutive integers that equal 126.
Divide 126 by 2 and choose the even numbers on both sides.
Let the intgers be n- 1 n , & n+1 . This is consecutive. Hence Adding (n-1) + n + ( n +1) = 126 Add the LHS 3n = 126 Divide both sides by '3' n = 42 Hence n- 1 = 41 & n +1 = 43 So the consecutive integers are 41,42, & 43.
124+125+126=375