Q: What three consecutive even numbers have a sum of 138?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

136 + 138+ 140

46 48 50 To explain: 3 even numbers. Call the first one x, then the next one will be x+2, and the third is x+4. (x)+(x+2)+(x+4)=144 3x + 6 = 144 3x = 138 x = 46 x+2 = 48 x+4 = 50

45, 46 and 47.

138

2,628,071 and 2,628,073. 138 cubed is 2,628,072

Related questions

136 + 138+ 140

The equation to solve this is... x + (x + 2) + (x + 4) = 138 x + x + x + 2 + 4 = 138 3x + 6 = 138 3x = 132 x = 44 x = 44 x + 2 = 46 x + 4 = 48 So, the three consecutive even numbers that add up to 138 are... 44, 46, & 48

The numbers are 45, 46 and 47.

Do-it-in-your-head method: The middle number MUST be a third of the total so 138 divided by 3 is 46, making your three numbers 44, 46 and 48. Shazam!

The integers are 44, 46 and 48.

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

The numbers are -48, -46 and -44 AND -47, -46, and -45. ( all negative numbers can be either odd or even)

The sets are 277, 279 and 136, 138, 140, 142.

138 is an even number.Any numbers that end with; 0, 2, 4, 6, or 8 are considered an 'Even' number.

what numbers go on after 138

The GCF of the given three numbers is 23

138 is, itself, an integer. It is impossible for any integer to lie between two consecutive integers.