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Three consecutive odd integers have a sum of 45 in algebraci expression?
Wiki User
∙ 14y ago
If x is the smallest odd integer, then x = 2n + 1 for some integer n.
Then the next two odd integers are 2n + 3 and 2n + 5
So the question then becomes:
2n+1 + (2n+3) + (2n+5) = 45
or 6n + 9 = 45 to be solved for n and thence the smallest of the three consecutive odd integers.
Wiki User
∙ 14y ago
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