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To solve the system given below using substitution it is best to start by solving the second equation for y 5x plus 2y equals 33 6y plus x equals 3?
Wiki User
∙ 9y ago
First of all, you haven't asked a question. But I'll just grab this tidbit and gambol
through the meadow with it anyway, as a pleasant springtime lark, tra la.
Let's do it your way: The second equation is 6y + x = 3 .
I changed my mind. Your suggestion was to solve this for 'y', but it's easier to solve it for 'x' instead, so I've decided to do this MY way after all.
Subtract 6y from each side: x = 3 - 6y Bring that along, while we look at the second equation: 5x + 2y = 33 Substitute the exprssion for 'x' that we derived a moment ago: 5(3-6y) + 2y = 33 Eliminate the parentheses: 15 - 30y + 2y = 33 Subtract 15 from each side: -30y + 2y = 18 Combine like terms on the left side: -28y = 18 Divide each side by -28: y = -18/28
y = -9/14 . Wonderful ! Substitute this into the second equation: 6(-9/14) + x = 3
x = 3 + 54/14 = 3 + 27/7
x = 21/7 + 27/7
x = 48/7. What delightful numbers! Nothing like obscuring the forest with so many trees
that the class never notices why you brought them there.
FYI ... I also tried it your way, on paper, and that doesn't make it any less messy.
Wiki User
∙ 9y ago
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Is it true or false that when using substitution is it best to start by solving the second equation for x?
If it's a simultaneous equation in x and y variables then x or y may be solved before substitution.
Solve using substitution x plus y equals 3 and y equals 9?
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
Solve this equation using substitution 3x plus 2y equals 2 and -2 plus y equals 8?
From second equation: y = 8 + 2xSubstitute for y in first equation: 3x + 16 + 4x = 2ie 7x = -14ie x = -2 and y = 4
Solve this equation using substitution 5x plus y equals 5 and 3x plus 2y equals 3?
From first equation: y = 5 - 5xSubstitute for y in second equation: 3x + 10 - 10x = 3ie -7x = -7ie x = 1 and y = 0
Solving systems by elimination method X plus y equals 2 and 2x plus 7y equals 9?
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
Is it true or false that when using substitution is it best to start by solving the second equation for x?
If it's a simultaneous equation in x and y variables then x or y may be solved before substitution.
To solve the system given below using substitution it is best to start by solving the second equation for y?
True
Solve using substitution x plus y equals 3 and y equals 9?
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
Solve this equation using substitution 3x plus 2y equals 2 and -2 plus y equals 8?
From second equation: y = 8 + 2xSubstitute for y in first equation: 3x + 16 + 4x = 2ie 7x = -14ie x = -2 and y = 4
Solve this equation using substitution 5x plus y equals 5 and 3x plus 2y equals 3?
From first equation: y = 5 - 5xSubstitute for y in second equation: 3x + 10 - 10x = 3ie -7x = -7ie x = 1 and y = 0
Solving systems by elimination method X plus y equals 2 and 2x plus 7y equals 9?
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
What is the second step in solving a nonlinear equation by substitution?
1. Substitute 2. Rearrange to equal zero 3. Factor if possible and use the zero product property to solve. 4. If you can't factor, graph and look for zeros (where it crosses the axis)
Is c equals ab to the second power a equation or expression?
It is an equation ... Anything with an equals is an equation 2+b=6 Anything without an equals is an expression 2+a
How do you find the locus of all points that lie on the graphs of both x plus 2y equals 1 and 2x -y equals 12?
You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".
What symbol will you find in every linear equation?
The equals sign ( = ). In fact it defines any equation, linear or not, since an equation is a statement that a particular value or term is equal to, so the result of solving, a second set of terms and operators. Any other symbols would be particular to the equation you have derived or are trying to solve.
Use the Substitution method to solve the system of equations y - 2x equals -5 3y - x equals 5?
From first equation: y = 2x - 5Substitute this in second equation: 3(2x - 5) - x = 5, ie 6x - 15 - x = 5ie 5x = 5 + 15 so x = 4 and y = 3
Describe the solution to the system of equations 5x - y equals 8 and 25x-5y equals 32?
Substitution method: from first equation y = 5x - 8. In the second equation this gives 25x - 5(5x - 8) = 32 ie 25x - 25x + 40 = 32 ie 40 = 32 which is not possible, so the system has no solution. Multiplication method: first equation times 5 gives 25x - 5y = 40, but second equation gives 32 as the value of the identical expression. No solution.
