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What symbol will you find in every linear equation?
The equals sign ( = ). In fact it defines any equation, linear or not, since an equation is a statement that a particular value or term is equal to, so the result of solving, a second set of terms and operators. Any other symbols would be particular to the equation you have derived or are trying to solve.
Use the substitution method to solve the following system of linear equations -3x-y equals 3 -3x-5y equals -21?
From first equation, -y = 3x + 3. Substitute in second equation: -3x + 5(3x + 3) = -21 ie 12x = -36 so x = -3 and y = -(-9 + 3) = 6. Easier method: subtract first equation from second giving -4y = -24 so y = 6, this in first equation gives -6 = 3x + 3, ie 3x = -9 so x = -3
How do you solve algebra with two variables?
Algebraic equations with two variables will need two equations to be able to solve it. Then, you can solve it with either substitution, adding/subtracting them together, or graphing! Those are the basic steps... For example: An instance of substitution: 2x + 1 = y + 2 x + y = 3 You could isolate y in the second equation to equal y = 3-x. Then in the first equation, substitute y with what it equals to 2x + 1 = 3-x+2 Then you can solve for x!
How do you do a 2 step equation?
When you are solving a 2-step equation, you do the opposite of a 1-step equation. You do addition and subtraction first, then the multiplication second. Example: 2x + 9=16 -9 -9 2x=7 Now it's a 1-step equation 2x=7 /2 /2 Your answer would be 3.5 To check all you do is replace the variable with your answer. 2x + 9=16 2(3.5) + 9=16
What is second order differential equation?
The highest order of derivative is 2. There will be a second derivative {f''(x) or d2y/dx} in the equation.
What is usually the second step when solving a system of nonlinear equations by substitution?
The second step when solving a system of nonlinear equations by substitution is to solve one of the equations for one variable in terms of the other variable(s). Once you have expressed one variable as a function of the other, you can substitute that expression into the other equation to create a single equation in one variable. This allows for easier solving of the system.
Is it true or false that when using substitution is it best to start by solving the second equation for x?
If it's a simultaneous equation in x and y variables then x or y may be solved before substitution.
To solve the system given below using substitution it is best to start by solving the second equation for y?
True
What is a non-linear equation?
A nonlinear equation does not produce a straight line and the exponent is to the second power or more. x square plus 3y =5 is an example of a nonlinear equation.
Solve using substitution x plus y equals 3 and y equals 9?
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
Is 5xto the second power plus xto the sixth power equals 12 linear or nonlinear?
Nonlinear
How do you find the locus of all points that lie on the graphs of both x plus 2y equals 1 and 2x -y equals 12?
You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".
Which situation may cause someone to use substitution in order to solve a system of equations?
Substitution is often used when one of the equations in a system is already solved for one variable, or can be easily manipulated to do so. For example, if you have the equations (y = 2x + 3) and (3x + 2y = 12), substituting the expression for (y) from the first equation into the second allows for straightforward solving. This method is particularly useful when dealing with linear equations, as it simplifies the process of finding the variable values.
Why euler method for solving first and second order differential equation is not preferred when compared with rungeekutta method?
"http://wiki.answers.com/Q/Why_euler_method_for_solving_first_and_second_order_differential_equation_is_not_preferred_when_compared_with_rungeekutta_method"
What is substitution of 4x-3y equals 1 x-2y equals 4?
To solve this system of equations using substitution, we can isolate one variable in one equation and substitute it into the other equation. From the second equation, we can express x in terms of y as x = 4 + 2y. Then, substitute this expression for x into the first equation: 4(4 + 2y) - 3y = 1. Simplify this equation to solve for y. Once you find the value of y, substitute it back into x = 4 + 2y to find the corresponding value of x.
Solve this equation using substitution 3x plus 2y equals 2 and -2 plus y equals 8?
From second equation: y = 8 + 2xSubstitute for y in first equation: 3x + 16 + 4x = 2ie 7x = -14ie x = -2 and y = 4
Solve this equation using substitution 5x plus y equals 5 and 3x plus 2y equals 3?
From first equation: y = 5 - 5xSubstitute for y in second equation: 3x + 10 - 10x = 3ie -7x = -7ie x = 1 and y = 0
