Cu+ H2O [OH + H3O= 2H2O]Copper plus more than one water = [CuOH + H3O]
13.7
1.39
6.6 x 10-9
3.4 * 10^-8
Cu+ H2O [OH + H3O= 2H2O]Copper plus more than one water = [CuOH + H3O]
13.7
1.39
H3o+
pH = -log(hydronium concentration) [Hydronium is H3O.-log(1 x 10-9) = 9
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
H3O is a strong acid.
Hydronium ions have the formula H3O+
-log(1.5*10-11) = 9.8pH
H2O is a polar molecule; +H3O is even more so.
6.6 x 10-9
No, it is an acid.