pH = -log(hydronium concentration) [Hydronium is H3O.
-log(1 x 10-9) = 9
.5M
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
Definition to use for the log (logarithm):the logarithm of a number (n) to a given base (b) is the exponent (e) to which the base must be raised in order to produce that number.(Raising to the power is the inverse of taking the logarithm.)logb(n) = e or be = nFor example, the logarithm of 1000 to base 10 is 3 ( log10(1000) = 3),because 10 to the power of 3 is 1000: 103 = 1000.-log10[H+] is (by definition) used to calculate the pH of a dilute solution in which [H+] = concentration of H+ (or H3O+) in mol/L.pH = -log10[H+] or [H+] = 10-pH
1.39
No, H3O+ (hydronium ion) is acidic. The presence of H3O+ in a solution indicates it is acidic in nature.
-log(1.5*10-11) = 9.8pH
p = -log[H+] = 12.4
Cu+ H2O [OH + H3O= 2H2O]Copper plus more than one water = [CuOH + H3O]
True
The concentration of H3O+ (hydronium ions) in a solution can be calculated using the formula pH = -log[H3O+], where [H3O+] represents the molarity of the hydronium ions. This formula relates the acidity of a solution to the concentration of hydronium ions present.
13.7
The concentration of an acid or base is measured in terms of the pH scale, which indicates the presence of H3O+ ions in solution. A lower pH value indicates a higher concentration of H3O+ ions, representing a more acidic solution. A higher pH value indicates a lower concentration of H3O+ ions, representing a more basic solution.
The pKa of H3O in aqueous solution is approximately -1.74.
The pH of the solution can be calculated using the formula pH = -log[H3O+]. Therefore, pH = -log(2 x 10^-14) ≈ 13.7. This means the solution is basic since the pH is above 7.
If the concentration of H3O+ ions is greater than the concentration of OH- ions in a solution, the solution is considered acidic. This imbalance indicates that there are more protons than hydroxide ions present, leading to an acidic pH.