The counting sequence is making increments of 11,
that is, the n-th term will = 11 x n
n = 12,
t = 12 x 11
= 132
11
In this case, 22 would have the value of 11.
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The nth term of the sequence is 2n + 1.
The nth term in this sequence is 4n + 3.
11
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
In this case, 22 would have the value of 11.
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The nth term of the sequence is 2n + 1.
The nth term in this sequence is 4n + 3.
3 11
94-1-6-11
It seems each term(except the first one obviously) is generated by adding 11 to previous one. 4 15 = 4 + 11 26 = 15 + 11 37 = 26 + 11 The next term in the sequence will be then: 48 = 37 + 11
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
It works out as -5 for each consecutive term
The 'n'th term is [ 4 - 3n ].