It works out as -5 for each consecutive term
The nth term of the sequence is 2n + 1.
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The nth term is 4n-1 and so the next term will be 19
The nth term of the sequence is (n + 1)2 + 2.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
It is: nth term = 29-7n
It is: nth term = 35-9n