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Q: Twice a number b in algebraic expression?

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b + 1 is b plus 1 as an algebraic expression.

The answer is b+1. Therefore the algebraic expression for this is b+1

(b - 7) should do it.

If the algebraic expression can be written in the form of a(x)/b(x) where a(x) and b(x) are polynomial functions of x and b(x) â‰ 0, then the expression is a rational algebraic expression.

Twice the difference between a number and thirteen can be written as 2 (b - 13) Five more than twice the difference between a number and thirteen can be written as 2 (b - 13) + 5. The algebraic expression is 2 (b - 13) + 5.

it's: a + b

b-7

Equation, not expression. A and B are two numbers. (A + B)2 = A2 + B2 + 2(AB) ----------------------------------

It is: b+b+b = 3b

9b2-7

6x+4 is the expression that you are looking for.

how can we convert algebraic expression into QBASIC a square + b square i = pTR/100 2xy mx+c a=r square a+b

It is 10/b.

a+b=c is a basic one.

You do not wright it, but write it as n + 6.

(a+b)/6

(a-b)(a^2 + ab + b^2)

6+b Should it not be: b>6

It could be a^3 + b or (a + b)^3, depending on the context.

Like this . . .B - 4 = 35and it is then an equation, not an expression.

A + B = C x = 2 + 6 It is an expression used to show an algebraic problem.

b - 15 = 28

21/b + 1

The algebraic expression is 3(b+5).

It is an algebraic expression in the form of: b+14