The algebraic expression is 3(b+5).
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7 + 3b ≥ 12 Subtract 7 from both sides: 3b ≥ 5 Divide both sides by 3: b ≥ 5/3 or 1.66...
It is: 5*(b+2) which is the same as 5b+10
1.Start 2. Input a,b,c 3. Sum = a+b+c 4. Average = sum/3 5. Output - Sum,Average 6. Stop
a + b = 14, so a = 14 - b; 6a - 3b = 3;substitute: 6(14 - b) - 3b = 3, ie 84 - 6b - 3b = 3, ie 81 = 9b so b = 9 and a = 5
We are looking for A B and C if they are consecutive odd integers B=A+2 and C=A+4 We are told 3B=5+A+C If we substitue the first two equations into the third 3(A+2)=5+A+(A+4) so 3A+6=2A+9 A=3 so B=5 and C=7