0
I'm assuming you mean 2((-8)(3x)).
2(-24x)
-48x
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∙ 14y ago
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What is the product of half the sum of -16 and 8 and twice the sum of -5 and 9?
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
How do you solve 3x2 plus 10x equals 8 by factoring?
3x² + 10x = 8 Rewrite as: 3x² + 10x - 8 = 0 The only way to get 3x² is 3x and x (3x + -- ) (x + --) The factors of 8 are {1 2 4 8} so the answers must be a pair of them. With 4 factors, and a negative sign (the -8), there are only 8 ways this can be written: (3x + 1)(x - 8) = 3x² - 23x - 8 (3x + 2)(x - 4) = 3x² -10x - 8 (almost) (3x + 4 )(x - 2) = 3x² - 8x - 8 (3x + 8)(x - 1) = 3x² +5x - 8 (3x - 1)(x + 8) = 3x² +23x - 8 (3x - 2)(x + 4) = 3x² + 10x -8 ◄ Success! (3x - 4)(x + 2) = 3x² +2x - 8 (3x - 8)(x + 1) = 3x² -5x - 8 Trial and error, error, error, is the key to this kind of problem. Seeing the -10x early can point you to see that maybe changing the signs can work. ■
What is 8 - 3x equals 128?
8 - 3x = 128subtract 8 from each side-3x = 120divide each side by -3x = -40
What is 3x times 8?
3x tomes 8
What is 57 decreased by twice a number?
Six less than the product of 8
Subtract 8 from the product of x and 3?
8
If 4 is added to twice a number and this sum is multiplied by 2 the result is the same as if the number is multiplied by 3 and 4 is added to the product What is the number?
Let the number be x: 2(2x+4) = 3x+4 4x+8 = 3x+4 4x-3x = 4-8 x = -4
The product of your number and 3 is the same product as twice 9 What is your number?
3x = 2 x 9 2 x 9 = 18 3x = 18 18/x = 6 Therefore, x = 6
What is twice the product of -8 and -16?
8
How do you write three times a number is equal to 8 more than twice the number?
It is: 3x = 2x+8 and the value of x is 8
How do you factor 3x 9y?
if it is 3x + 9y, then 3(x+3y) or if it is a product...then it doesn't make sense, since then 3x9y=27xy
What is the product of half the sum of -16 and 8 and twice the sum of -5 and 9?
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
How do you write the sum of three times a number and -4 is at least twice the number plus 8?
3x + (-4) ≥ 2x + 8
What expressions represents the product of 3 less than twice x and 2 more than the quantity 3 times x?
Three less than twice x is 2x-3.Two more than the quantity 3 times x is 3x + 2.The product of these is (2x-3)(3x+2), which can also be written as:(6x2 - 5x - 6)
What represents the product of 3 less than twice x and 2 more than the quantity 3 times x?
Three less than twice x is 2x-3.Two more than the quantity 3 times x is 3x + 2.The product of these is (2x-3)(3x+2), which can also be written as:(6x2 - 5x - 6)
How do you solve 3x2 plus 10x equals 8 by factoring?
3x² + 10x = 8 Rewrite as: 3x² + 10x - 8 = 0 The only way to get 3x² is 3x and x (3x + -- ) (x + --) The factors of 8 are {1 2 4 8} so the answers must be a pair of them. With 4 factors, and a negative sign (the -8), there are only 8 ways this can be written: (3x + 1)(x - 8) = 3x² - 23x - 8 (3x + 2)(x - 4) = 3x² -10x - 8 (almost) (3x + 4 )(x - 2) = 3x² - 8x - 8 (3x + 8)(x - 1) = 3x² +5x - 8 (3x - 1)(x + 8) = 3x² +23x - 8 (3x - 2)(x + 4) = 3x² + 10x -8 ◄ Success! (3x - 4)(x + 2) = 3x² +2x - 8 (3x - 8)(x + 1) = 3x² -5x - 8 Trial and error, error, error, is the key to this kind of problem. Seeing the -10x early can point you to see that maybe changing the signs can work. ■
How do you solve 8-3x equals 128?
8-3x = 128 -3x = 128-8 -3x = 120 x = -40
