8-3x = 128
-3x = 128-8
-3x = 120
x = -40
find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
x = 64 64 + 64 = 128
5.
X is 6
128 = x7 (we see that x > 0, since x is raised to an odd power) 27 = x7 (this is true only when x = 2) 2 = x Remember that a logarithm is an exponent. The statement 128 = x7 is equivalent to logx 128 = 7. logx 128 = 7 log 128/log x = 7 (or reverse the both sides) log x/log 128 = 1/7 (multiply by log 128 to both sides) log x = log128/7 (or use base 10 for the logarithm) log10 x = log128/7 (write the equivalent statement) 10log 128/7 = x 2 = x or use the natural log, ln. 128 = x7 ln 128 = ln x7 ln 128 = 7ln x (ln 128)/7 = ln x e(ln128)/7 = elnx (elnx = x ) 2 = x
83x + 523 is an algebraic expression. Were this expression set to be equal to something, one could then solve this expression for x.
128
128
3x - 4 = 83x = 8+43x = 12x = 12/3 = 4
The number that, when raised to the power of 2, equals 128 is the square root of 128. The square root of 128 is approximately 11.31. Therefore, 11.31 raised to the power of 2 equals 128.
128 oz equals 8 pounds.
% rate = 160% = 128/80 * 100% = 1.6 * 100% = 160%
To solve x + x + x + x, set the problem up as multiplication like this 4x = 128. Divide both sides of the problem by 4. You will get x = 32. To check your work, substitute 32 for the x and do the math. 4 x 32 = ?. If the answer is 128, the answer is correct.
128 fluid ounces
16
what if someone has a number already to add with another number to equal 128, so 64+64 still equals 128.
that is impossible you idiot