8-3x = 128
-3x = 128-8
-3x = 120
x = -40
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find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
x = 64 64 + 64 = 128
5.
X is 6
128 = x7 (we see that x > 0, since x is raised to an odd power) 27 = x7 (this is true only when x = 2) 2 = x Remember that a logarithm is an exponent. The statement 128 = x7 is equivalent to logx 128 = 7. logx 128 = 7 log 128/log x = 7 (or reverse the both sides) log x/log 128 = 1/7 (multiply by log 128 to both sides) log x = log128/7 (or use base 10 for the logarithm) log10 x = log128/7 (write the equivalent statement) 10log 128/7 = x 2 = x or use the natural log, ln. 128 = x7 ln 128 = ln x7 ln 128 = 7ln x (ln 128)/7 = ln x e(ln128)/7 = elnx (elnx = x ) 2 = x