find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
x = 64 64 + 64 = 128
128 = x7 (we see that x > 0, since x is raised to an odd power) 27 = x7 (this is true only when x = 2) 2 = x Remember that a logarithm is an exponent. The statement 128 = x7 is equivalent to logx 128 = 7. logx 128 = 7 log 128/log x = 7 (or reverse the both sides) log x/log 128 = 1/7 (multiply by log 128 to both sides) log x = log128/7 (or use base 10 for the logarithm) log10 x = log128/7 (write the equivalent statement) 10log 128/7 = x 2 = x or use the natural log, ln. 128 = x7 ln 128 = ln x7 ln 128 = 7ln x (ln 128)/7 = ln x e(ln128)/7 = elnx (elnx = x ) 2 = x
5.
X is 6
83x + 523 is an algebraic expression. Were this expression set to be equal to something, one could then solve this expression for x.
128
128
3x - 4 = 83x = 8+43x = 12x = 12/3 = 4
128 oz equals 8 pounds.
To solve x + x + x + x, set the problem up as multiplication like this 4x = 128. Divide both sides of the problem by 4. You will get x = 32. To check your work, substitute 32 for the x and do the math. 4 x 32 = ?. If the answer is 128, the answer is correct.
% rate = 160% = 128/80 * 100% = 1.6 * 100% = 160%
128 fluid ounces
16
what if someone has a number already to add with another number to equal 128, so 64+64 still equals 128.
25.6 x 5 = 128
78 + 50 = 128