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If we include both 1 and 50 there are 50 numbers to choose from. The numbers that are divisible by 7 in that range are 7, 14, 21, 28, 35, 42,and 49. There are 7 of them. So the answer would be 7 out of 50, which is 14%.
The event space comprises the numbers 10 to 99, 90 such numbers. The favourable events are 15, 21, 27, ... , 99. There are 15 such numbers. So the probability is 15/90 = 1/6
The theoretical probability of getting an odd product would depend on the specific scenario. If we are talking about rolling a pair of fair dice, the probability would be 1/2 since half of the possible outcomes (3, 5, 15, etc.) would result in an odd product. However, if we are talking about multiplying two randomly selected numbers from a large set, the probability would depend on the distribution of the numbers in the set.
Randomly selected from 0 to 90.
The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.
If we include both 1 and 50 there are 50 numbers to choose from. The numbers that are divisible by 7 in that range are 7, 14, 21, 28, 35, 42,and 49. There are 7 of them. So the answer would be 7 out of 50, which is 14%.
The event space comprises the numbers 10 to 99, 90 such numbers. The favourable events are 15, 21, 27, ... , 99. There are 15 such numbers. So the probability is 15/90 = 1/6
Randomly selected from 0 to 90.
The theoretical probability of getting an odd product would depend on the specific scenario. If we are talking about rolling a pair of fair dice, the probability would be 1/2 since half of the possible outcomes (3, 5, 15, etc.) would result in an odd product. However, if we are talking about multiplying two randomly selected numbers from a large set, the probability would depend on the distribution of the numbers in the set.
Assuming then that there are 100 numbers, 1-100, the probability of the number 23 being randomly picked out of 100 is: 1/100 or 0.01.
There is 100% chance.
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.The answer depends on how many numbers are selected.
Yes!
There are infinitely many numbers and so the probability of the second event is 0. As a result the overall probability is 0.
5/24, or five out of twenty four, or with numbers, five out of infinity
Depending on what numbers are you picking from: {Integers, Whole Numbers, Natural numbers, All real numbers} will affect the probability.