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Q: What is the probability of getting two prime numbers 1-10?

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20, 40, 50

110

About 48% or if you want to be more accurate the actual answer was 47.826%

The chance of not winning on one attempt is 1 - 0.008 = 0.992 The chance of not winning over 110 attempts is therefore 0.992110, since you must fail every time. 0.992110 = 0.413 (to three decimal places). (It follows that 0.587 is the chance of winning on at least one attempt.)

With a mean score of 110 and a standard deviation of 18, what percentage of scores would be less than 155?

Related questions

ANSWER: The prime numbers between 110 - 130 are 113 and 127.

2x5x11=110

The prime numbers from 100 to 110 are 101, 103, 107, and 109.

The prime factors of 110 are 2, 5 and 11.

Negative numbers don't have prime factorizations.

113.

2,5, and 11.

The numbers 97, 101, 103, 107 and 109 are prime.

The prime numbers between the prime number 101 and the composite number 110 are 103, 107, and 109.

2, 5, 11

420

They are: 113 127

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