8+8+8+8+8+8+8/8 = 49
You can add eight 8s to get 1000 by arranging them as follows: 888 + 88 + 8 + 8 + 8 = 1000. This way, you effectively use the eight 8s in a combination that sums to the desired total.
8 - 8/8 = 8 - 1 = 7
64 = 8 x 8 !
There are four 8s in 32, as 32 divided by 8 equals 4. This means that if you take four 8s (8 + 8 + 8 + 8), you will sum up to 32.
-- Split the 8s up into two groups of four. -- Do any kind of arithmetic or algebra you want to with one group of four 8s. -- Do exactly the same thing with the other group of four 8s, and give it a negative sign. -- Add the two groups of 8s. The sum is zero.
To find out how many 8s are in 48, you divide 48 by 8. The calculation is 48 ÷ 8 = 6. Therefore, there are six 8s in 48.
eights, 8s
8s or eights.
You can make 1000 using eight 8s by arranging them in the following equation: (888 + 88 + 8 + 8 + 8 = 1000). This utilizes the digits effectively while adhering to the requirement of using exactly eight 8s.
8s = 72 divide both sides by 8 s = 9
8s=ps=p/8
Oh, what a happy little math problem we have here! Let's see, if we take 49 and divide it by 8, we find that 6 whole 8s fit in, with a remainder of 1. Isn't that just lovely? Remember, it's all about enjoying the process of discovering the answer, my friend.