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Q: WHAT IS THE 4 BIT BINARY NUMBER ASSOCIATED WITH HEXADECIMAL SYMBOL C?

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It is 1100.

Binary(1010) = Hex(A)

It is A.

1100

1010 = A

It is E.

1100

0xc = 1100 Hexadecimal digits use exactly 4 binary digits (bits). The 0x0 to 0xf of hexadecimal map to 0000 to 1111 of binary. Thinking of the hexadecimal digits as decimal numbers, ie 0x0 to 0x9 are 0 to 9 and 0xa to 0xf are 10 to 15, helps with the conversion to binary: 0xc is 12 decimal which is 8 + 4 → 1100 in [4 bit] binary.

It is EIt is EIt is EIt is E

1100(2)=C(16)=12(10)

It is only true in the sense that any numeric base, expressed in that base, is represented with the symbol "10". Confusing? Let's clarify that. Hexadecimal numbers use sixteen as the base. But how do you express the value sixteen in hexadecimal? Quite easy, it would be written as "10". The same is true in any other base. For example, in binary (base two), the value two is expressed as "10". In octal (base eight), the value eight is expressed as "10". In decimal (our familiar base ten), the value ten is expressed as "10". No matter what base you work in, the base itself will always be expressed as "10". That however is not the same thing as saying that hexadecimal numbers are based on the number ten. That is incorrect. Hexadecimal numbers use the base sixteen.

5 symbols-A,B,C,D,E,F

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