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Wap to test whether the given no is divisible by both 11 and 13?
Wiki User
∙ 13y ago
First check if it is divisible by 13. You need to delete the last digit from the number, then subtract 9 times the deleted
digit from the remaining number. If what is left is divisible by 13,
then so is the original number.
For example. 195
The last digit is 5 so we delete that. Now 9x5=45 and we must subtract that from 195
So we have 19-45=-26 which is clearly divisible by 13.
Now for 11 you need another test.
Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)
If the result (including 0) is divisible by 11, the number is also.
Example: to see whether 365167484 is divisible by 11, start by subtracting:
[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11.
If your numbers passes both the divisibility tests, for 11 and 13, then it is divisible by both.
Wiki User
∙ 13y ago
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Is 8 264 divisible by 3?
To test whether a number is divisible by 3, the sum of its digits must also be divisible by 3. In this instance, the sum of the digits of 8264 is equal to 20. Therefore, since 20 is not divisible by 3, nor is 8264.
If a number is expressed in binary what is a necessary and sufficient condition to test whether it is divisible by 2?
Sweet dreams are made of cheese.
What is the greatest number to test whether 2558 is prime?
If its divisible by 2 then it's not a prime number. But 2 by itself is a prime number
Divisibility of 7623?
7623 is divisible by 3.Test of divisibility by 3:Sum of digits of 7623 = 7+6+2+3 = 18, which is a multiple of 3, so the number is divisible by 3.If sum of the digits of a number is a multiple of 9 then it is divisible by 9.So, 7623 is also divisible by 9.Therefore, test of divisibility can help a lot in determining whether a number is divisible by any other number.
What are the divisibility rule for 6?
To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3→ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3→ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3→ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3→ 121 is not divisible by either 2 or 3, so it is not divisible by 6
If a number is expressed in binary. what is a necessary and sufficient condition to test whether it is divisible by 2?
The last digit is zero.
How do you write a program to test if a given number is divisible by 6 in C programming?
if ( x % 6 == 0 ){ printf( "%d is divisible by 6", x ); } else { printf( "%d is not divisible by 6", x ); }
Is 8 264 divisible by 3?
To test whether a number is divisible by 3, the sum of its digits must also be divisible by 3. In this instance, the sum of the digits of 8264 is equal to 20. Therefore, since 20 is not divisible by 3, nor is 8264.
How do know a number is divisible by six?
It's very easy to test a number to see if it is divisible by 4 or by 9. If it passes both tests, then it is divisible by 4x9=36.To test for divisibility by 9, add the digits of the number. If the sum is divisible by 9, then the number is divisible by 9.To test for divisibility by 4, look at the last two digits. If they are a multiple of 4, then the number is divisible by 4.
If a number is expressed in binary what is a necessary and sufficient condition to test whether it is divisible by 2?
Sweet dreams are made of cheese.
How test whether 58734 is divisible by 9?
Add up the digits. If the total is a multiple of 9, the whole number is a multiple of 9.
What is the greatest number to test whether 2558 is prime?
If its divisible by 2 then it's not a prime number. But 2 by itself is a prime number
Divisibility of 7623?
7623 is divisible by 3.Test of divisibility by 3:Sum of digits of 7623 = 7+6+2+3 = 18, which is a multiple of 3, so the number is divisible by 3.If sum of the digits of a number is a multiple of 9 then it is divisible by 9.So, 7623 is also divisible by 9.Therefore, test of divisibility can help a lot in determining whether a number is divisible by any other number.
What are the divisibility rule for 6?
To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3→ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3→ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3→ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3→ 121 is not divisible by either 2 or 3, so it is not divisible by 6
How do you test if a number is divisible by 6?
If it is divisible by 2 and 3
What does a vertical line test mean?
Determines whether a given mathematical expression is a function or not.
How do you Test if a number is divisible by 3?
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
