Add up the digits. If the total is a multiple of 9, the whole number is a multiple of 9.
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You test by := All EVEN Numbers are divisible by '2' All numbers ending in '5' or ''0' are divisible by '5' All numbers whose digits add to '9' are divisible by '9'. e.g. 234 2+3+4 = 9 All numbers whose form is ' m(m+n)n ' e.g. 132 are divisible by '11'. This leaves only '3' and '7' to test by actual division.
6 + 4 + 6 = 16 1 + 6 = 7 → No; 646 is not divisible by 9 (there is a remainder of 7). ----------------------------------------- Only if the sum of the digits is divisible by 9 is the original number divisible by 9. Repeat the test on the sum until a single digit remains; only if this single digit is 9 is the original number divisible by 9, otherwise this single digit is the remainder when the original number is divided by 9.
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
18324 is divisible by both 4 and 9. 18324 / 4 = 4581 18324 / 9 = 2036 You can simply check if a number is divisible by 4 if the last two digits are divisible by 4. The last two digits are 24. 24 is divisible by 4. (24/4=6) An easy way to check if a number is divisible by 9 is if sum of the digits are divisible by 9. 18324 1+8+3+2+4 =18 18 1+8 =9 9 is divisible by 9, so 18324 is divisible by 9.
No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5