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Q: What are the x and y intercepts for y=x^2-2x+2?

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The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.

The x and y intercepts are where a line on a graph intersects (crosses over) the x or y axis.

Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.

the x is dependent and the y is independent and the x numbers cant repeat themself and yes they do have intercepts

In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.

X intercept: -5 Y intercept: +3

Then there is no x-intercept. No big deal. Lots of functions do not have x- intercepts. For example, y = x2 + 1 or y = 2x

The cosecant function, being defined as 1÷sin(x), has no x intercepts. It has y intercepts at ±∞. (infinity and -infinity)

Ax+By=C

0.

5x²=0 X=0 the function y=5x² only intercepts x when x = 0

If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).

The 'x' and 'y' intercepts of that equation are both at the origin.

A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.

y = -xBoth intercepts are at the origin. From there, the line slopes up to the leftand down to the right.

YES, all linear equations have x-intercepts. because of the x, y has to be there 2!

12

For the x intercepts, y = 0 ie 0 = 2x2 + 2x - 4 or x2 + x - 2 = 0 so that (x + 2)*(x - 1) = 0 So the intercepts are (-2,0) and (1,0)

Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.

They are at: x = -2.5 and x = 4

Factoring a quadratic allows you to solve the x and y intercepts. The x-intercepts in the factored form are the inverse of the constants. The y-intercept is the product of the x-intercepts multipied together. Example: x²-10x-24 = (x+2)(x-12) +2 and -12 are the constants. So ur x-intercepts are (-2,0) (12,0). The y intercept is -24 because -2 X 12 = -24.

8

y intercept is 1 x intercept is .5

The y intercept is 10 and the x intercept is -4

There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.